name | correct guesses | games together | ratio |
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name | correct guesses | games together | ratio |
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1 2 3 4 5 6 7 8 | n = 1 while n <= 100: r = "" if n % 3 == 0: r = "Fizz" if n % 5 == 0: r += "Buzz" if r == "": print(n) else: print(r) n += 1 |
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 | #define Clear_The_Page system("cls||clear"); #define Read_Me_The_Story printf("\t:: \"%s\" by %s ::\n", story, argv[1]); {int i = 0; while (i < 65536 && story[i]) {i++;} for (i = i + 1; story[i] && i < 65536; i++) {printf("%c", story[i]);} printf("\n");} #define Close_The_Book(reason) return reason #define Unknown_Author 1 #define All_Is_Good 0 #define Write_Me_A_Story char c; int x = -1, y = -1; while ((c = fgetc(author)) != EOF) {{if ((57 >= c && c >= 48) || (71 >= c && c >= 65)) {if (x == -1)x = (c < 65? (c - 48): (10 + c - 65)) * 16;else {y = (c < 65? (c - 48): (10 + c - 65)) + x;x = -1;if (y == 8) --pen;else if (y == 255) ++pen;else {*pen += y;++pen;}}}}} #define Check_It_Out if (argc < 2) {printf("ws: no author was provided\n");Close_The_Book(Unknown_Author);}if (!author) {printf("ws: could not reach the author\n");Close_The_Book(Unknown_Author);} /* hey, nurdle here! * warning to all aspiring codeguessers: * in the info page when they say "we don't bite" they are lying. * they have had incidents where they did in fact use their sharp teeth (especially back when they were allowed to roam around during the day, pre-87') to cause bodily harm * to several children attending the events at the pizzeria (Lyicly's Dinner). * I wish to remind you to KEEP ALL OF YOUR LIMBS A SAFE DISTANCE OF 30 CM AWAY FROM THEIR MOUTHS. * thank you and have a blessed day! */ |
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 | # writeScript! wS programs start with a 65536 byte long tape where every byte by default = 0<br> wS programs are comprised of hexidecimal numbers (non hex characters are ignored), these represent addition<br> NOTE: hex numbers `A-F` MUST BE CAPITALIZED, lowercase letters are for comments. ## Control Characters * `08` goes back to the previous character in the tape * `ff` skips to the next character in the tape the first string represents the title of the book, while the second string represents the contents of the book.<br> the title and contents of the book are seperated by null characters. ```wS 41 00 42 ``` this book would be titled "A" (which is 41 in hex) and its contents would be "B" (which is 42 in hex) ## Running The "Emulator" compile the `ws.c`, and then run it using the format below ```bash ./ws (filename) ``` |
1 2 | 47 65 6C 6C 6F 20 51 6F 72 6C 64 21 00 name of book 47 65 6C 6C 6F 20 51 6F 72 6C 64 21 00 contents |
1 2 3 4 5 6 | why cant i say everyone is lyingly? what is up with that? another err 500? another err 404? another err in general? the anonymous is rigged to target new CGers in every way, therefore you should use it so that it isnt rigged. this code was not written by me, however someone probably did |
1 2 3 4 5 6 7 8 | #include <stdio.h> #include <stdlib.h> #include "cool.h" FILE *author; char story[65536] = {0}; char *pen = story; int main(int argc, char **argv) { author = fopen(argv[1], "r"); Check_It_Out; Clear_The_Page; Write_Me_A_Story; Read_Me_The_Story; Close_The_Book(All_Is_Good);} |
1 | 100000000 |
1 2 | # Monsexevensunsexmonsexday * meet with Zero |
1 | cg: couldn't decode file contents |
1 | cg: couldn't decode file contents |
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 | import math # turn base6 into standard integer def m(n: str): # setup m = 1 numerals = "012345" n = n[::-1] x = 0 for i in n: x += numerals.index(i) * m m *= len(numerals) return x # turn integer into base6 def x(n: int): i = 0 x = "" numerals = "012345" y = n while y > 0: x += numerals[y % 6] y = math.floor(y / 6) if x == "": return "0" return x[::-1] |
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 | # the names of numbers d = { "423": "y", "69": "funny", "49": "wedne", "20": "satur", "13": "devil", "12": "dozen", "11": "leven", "10": "deca", "0": "zero", "1": "mon", "2": "tue", "3": "thur", "4": "four", "5": "fri", "6": "sex", "7": "seven", "8": "octo", "9": "sun" } # get the name of the numbers def getName(num, plural=False): n = str(num) ret = "" i = 0 while i < len(n): for ii in d: if n[i:].startswith(ii): ret += d[ii] i += len(ii) -1 break i += 1 if plural: return (ret + 's').replace("fris", "fries").replace("ys", "ies").replace("xs", "x") else: return ret |
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 | # // Code by SoundOfSpouting#6980 (UID: 151149148639330304). // Code by # SoundOfSpouting#6980 (UID: 151149148639330304). SHUT THE FUCK UP. Like, # wow. Jesus f-ing christ. I can't TAKE IT ANY MORE. All you esolangers # think you're soooo funny, huh. Laughing at people who don't get your # silly little injokes. // Code by SoundOfSpouting#6980 (UID: 1511491486 # 39330304). What the fuck does that even mean?? Huh??? It's not funny! A # joke is supposed to be funny, not some weird string of random words that # doesn't even make sense! I'm sick and tired of these elitist shmucks # thinking they own the whole place just because they laugh at // Code by # SoundOfSpouting#6980 (UID: 151149148639330304). Oh I'm so smart because # // Code by SoundOfSpouting#6980 (UID: 151149148639330304). Oh I'm so # cool. Ha ha ha. Well you know what, I can laugh at it too. HA HA HAHAHA. # I'm laughing at how PITIFUL and DERANGED you people are. That's the # joke. That's the real funny part about // Code by SoundOfSpouting#6980 # (UID: 151149148639330304), that anyone would stoop so low to ever make a # joke on how a discord tag is suddenly the peak of humour. Get a grip, # you losers. // Code by SansOfUndertale#0413 (UID: 403033936841941151). # Hardyhardyhar. import libs.base6 as b6 import math from libs.num_names import getName import time unsolvable = "```\n....................../´¯/) \n....................,/¯../ \n.................../..../ \n............./´¯/'...'/´¯¯`·¸ \n........../'/.../..../......./¨¯\ \n........('(...´...´.... ¯~/'...') \n.........\.................'...../ \n..........''...\.......... _.·´ \n............\..............( \n..............\.............\...\n```" def main(): # setup out = open("IO/output.md", "w") # get the input friends = open("IO/input.txt", "r") friends = friends.read() # split the list friends = friends.split("\n") # this is to prevent an error from occuring if the user gives invalid input try: # get the value of the numbers provided (the days that friends are available on) friends = [[b6.m(ii) for ii in i.split(" ")] for i in friends] except: # flip the user off out.write(unsolvable) # close the output file out.close() print("woops! input must be in seximal (base 6) (only 0,1,2,3,4,5 are allowed)") # end the program return friend_count = len(friends) # map out the days, this is to get rid of days that no one is available for (provides large preformance boost) day_map = [] for i in friends: if not i in day_map: day_map.append(i) # sort the map from earliest to latest day_map.sort() day_count = len(day_map) # get the number of days each friend is available for p_o = [len(i) for i in friends] p = 1 # count the number of possible schedules/combinations for i in p_o: p *= i # if the amount of possibilities is 0 then it is unsolvable and therefore the program will flip you off if p == 0: # flip the user off out.write(unsolvable) # close the output file out.close() # end the program return # setup i = 0 # this loop will run through every possible variation and try to find one that doesn't require two friends to occupy the same day # if it can't find a solution it will flip you off while i < p: # setup days = [-1] * day_count ii = 0 g = i fail = False # check the current variation while ii < friend_count: # unexplainable dark magic that selects an available day of one of the friends x = g % p_o[ii] # check if the selected day isn't already taken by another friend if days[x] == -1: days[x] = ii else: # if it is taken then we know this combination won't work, so move on to the next combination fail = True break # some more unexplainable dark magic that is required for this system to work g = math.floor(g / p_o[ii]) ii += 1 if not fail: # setup export = "" ii = 0 while ii < day_count: # name for the day day_name = getName(day_map[ii], plural=True) day_name = day_name.capitalize() friend_name = getName(days[ii]) # make friend 1's name and 2's name sound cooler friend_name = friend_name.replace("tue", "thue").replace("mon", "mono") friend_name = friend_name.capitalize() # format it into readable markdown export += "# {0}day \n* meet with {1}\n".format(day_name, friend_name) ii += 1 # write to the file out.write(export) # close the output file out.close() # end the program return i += 1 # if the problem is unsolvable, the program will flip you off # flip the user off out.write(unsolvable) # close the file out.close() # end the program return start = time.time() # error "handling" try: main() except Exception as e: print("there was an error") raise Exception delay = round(time.time() - start, 3) print("program finished ({0}s)".format(str(delay))) |
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